Quadratic Equations Exercise 9.10 – Class X

I.Solve the following equations graphically.

(i) x2 – 4x = 0

(ii) x2 + x – 12 = 0

(iii) x2 – x – 2 = 0

(iv) x2 – 5x + 6 = 0

II.

  1. Draw the graph of y = x2 and find the value of √3
  2. Draw the graph of y = 2x2 and find the value of √7
  3. Draw the graph of y = 1/2y2 and find the value of √10

Quadratic Equations – Exercise 9.10 – Solutions:

I.Solve the following equations graphically.

(i) x2 – 4x = 0

Solution:

Prepare the table of the values for the equation y = x2 – 4x

x-1012345
y50-3-4-305

Quadratic Equation Exercise 9.10

The parabola intersects the x – axis at (0, 0) and (4, 0)

Therefore, the roots of equation are 0 and 4.


 (ii) x2 + x – 12 = 0

Solution:

Prepare the table of the values for the equation  x2 + x – 12 = 0

x-4-3-2-101234
y06-10-12-12-10-608

Quadratic Equation Exercise 9.10
The parabola intersects the x – axis only at (3, 0) and (-4, 0)

Therefore, the roots of equation are 3 and -4.


(iii) x2 – x – 2 = 0

Solution:

Prepare the table of the values for the equation  x2 – x – 2 = 0

x-2-10123
y40-2-204

Quadratic Equation Exercise 9.10

The parabola intersects the x – axis at (-1, 0) and (2, 0)

Therefore, the roots of equation are -1 and 2.


 (iv) x2 – 5x + 6 = 0

Solution:

Prepare the table of the values for the equation y = x2 – 5x + 6

x012345
y620026

Quadratic Equation Exercise 9.10

The parabola intersects the x – axis at (2, 0) and (3, 0)

Therefore, the roots of equation are 2 and 3.

 


II.

  1. Draw the graph of y = x2 and find the value of √3

Solution:

y = x2

x0-11-22√3
y011443

Quadratic Equation Exercise 9.10

When x = √3, y = (√3)2 = 3

Draw a straight line y = 3 parallel to x-axis

The point on x – axis at which the perpendiculars meets are the values of √3 , x = ±1.7

Therefore, √3 = ±1.7

  1. Draw the graph of y = 2x2 and find the value of √7

Solution:

y = 2x2

x0-11-22-33√7
y02288181814

Quadratic Equation Exercise 9.10

When x = √7, y = 2(√7)2 = 14

Draw a straight line y = 14 parallel to x-axis.

The point on x – axis at which the perpendiculars meets are the values of √7 , x = ±2.6

Therefore, √7 = ±2.6

 

  1. Draw the graph of y = 1/2x2 and find the value of √10

Solution:

y = 1/2x2

x0-22-44√10
y022885

Quadratic Equation Exercise 9.10

When x = √10, y = 1/2(√10)2 = 5

Draw a straight line y = 5 parallel to x-axis.

The point on x – axis at which the perpendiculars meets are the values of √10 , x = ±3.1

Therefore, √10 = ±3.1